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makepkg: remove distcc/makeflags option interaction

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Way back in c94bfbaba when refactoring makepkg options handling, I added
these lines to unset MAKEFLAGS if '!distcc' was set in a PKGBUILD (not
taking into account makepkg.conf settings). This was an attempt to say
"if it is broken in distcc, it is probably broken even more". However,
this is silly as one should be using '!makeflags' as well. Remove the
linkage.

Signed-off-by: Dan McGee <dan@archlinux.org>
This commit is contained in:
Dan McGee 2011-06-23 15:19:01 -05:00
parent 54ef162a1a
commit aa89a65a83
1 changed files with 0 additions and 3 deletions
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3
scripts/makepkg.sh.in
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@ -822,9 +822,6 @@ run_build() {
if [[ $(check_buildenv distcc) = "y" && $(check_option distcc) != "n" ]]; then
[[ -d /usr/lib/distcc/bin ]] && export PATH="/usr/lib/distcc/bin:$PATH"
export DISTCC_HOSTS
elif [[ $(check_option distcc) = "n" ]]; then
# if it is not wanted, clear the makeflags too
MAKEFLAGS=""
fi
# use ccache if it is requested (check buildenv and PKGBUILD opts)