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Fixed test 1309 to pass the torture test

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Removing dynamic allocations also simplifies the test.
This commit is contained in:
Dan Fandrich 2011-06-11 00:10:09 -07:00
parent c4dd8df081
commit b688f2c260
1 changed files with 9 additions and 12 deletions
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21
tests/unit/unit1309.c
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@ -70,25 +70,20 @@ UNITTEST_START
/* number of nodes to add to the splay tree */ /* number of nodes to add to the splay tree */
#define NUM_NODES 50 #define NUM_NODES 50
struct Curl_tree *root, *t; struct Curl_tree *root;
void *ptrs[NUM_NODES]; struct Curl_tree nodes[NUM_NODES];
int rc; int rc;
int i; int i;
root = NULL; /* the empty tree */ root = NULL; /* the empty tree */
for(i = 0; i < NUM_NODES; i++) { for(i = 0; i < NUM_NODES; i++) {
struct timeval key; struct timeval key;
ptrs[i] = t = malloc(sizeof(struct Curl_tree));
if(!t) {
puts("out of memory!");
return 0;
}
key.tv_sec = 0; key.tv_sec = 0;
key.tv_usec = (541*i)%1023; key.tv_usec = (541*i)%1023;
t->payload = (void *)key.tv_usec; /* for simplicity */ nodes[i].payload = (void *)key.tv_usec; /* for simplicity */
root = Curl_splayinsert(key, root, t); root = Curl_splayinsert(key, root, &nodes[i]);
} }
puts("Result:"); puts("Result:");
@ -99,11 +94,13 @@ UNITTEST_START
printf("Tree look:\n"); printf("Tree look:\n");
splayprint(root, 0, 1); splayprint(root, 0, 1);
printf("remove pointer %d, payload %ld\n", rem, printf("remove pointer %d, payload %ld\n", rem,
(long)((struct Curl_tree *)ptrs[rem])->payload); (long)(nodes[rem].payload));
rc = Curl_splayremovebyaddr(root, (struct Curl_tree *)ptrs[rem], &root); rc = Curl_splayremovebyaddr(root, &nodes[rem], &root);
if(rc) if(rc) {
/* failed! */ /* failed! */
printf("remove %d failed!\n", rem); printf("remove %d failed!\n", rem);
fail("remove");
}
} }
UNITTEST_STOP UNITTEST_STOP