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in unescape(), '+' is now only converted to space after the first '?'

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This commit is contained in:
Daniel Stenberg 2000-08-31 12:03:04 +00:00
parent 1cedcce3e9
commit 60eab89f10
1 changed files with 17 additions and 7 deletions
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24
lib/escape.c
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@ -41,6 +41,9 @@
/* Escape and unescape URL encoding in strings. The functions return a new
* allocated string or NULL if an error occurred. */
#include "setup.h"
#include <curl/curl.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
@ -88,17 +91,24 @@ char *curl_unescape(char *string, int length)
unsigned char in;
int index=0;
int hex;
char querypart=FALSE; /* everything to the right of a '?' letter is
the "query part" where '+' should become ' '.
RFC 2316, section 3.10 */
while(--alloc) {
in = *string;
if('+' == in)
in = ' ';
if(querypart && ('+' == in))
in = ' ';
else if(!querypart && ('?' == in)) {
/* we have "walked in" to the query part */
querypart=TRUE;
}
else if('%' == in) {
/* encoded part */
if(sscanf(string+1, "%02X", &hex)) {
in = hex;
string+=2;
}
/* encoded part */
if(sscanf(string+1, "%02X", &hex)) {
in = hex;
string+=2;
}
}
ns[index++] = in;