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Fix for manual and backlog searches to insure maximum results are returned

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echel0n 2014-05-13 13:38:32 -07:00
parent 98e1d67cf9
commit b8a499b3d3
1 changed files with 18 additions and 13 deletions
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7
sickbeard/search.py
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@ -319,7 +319,7 @@ def searchProviders(queueItem, show, season, episodes, seasonSearch=False, manua
logger.ERROR) logger.ERROR)
return [] return []
for provider in providers: for providerNum, provider in enumerate(providers):
foundResults = {provider.name:{}} foundResults = {provider.name:{}}
try: try:
@ -523,6 +523,7 @@ def searchProviders(queueItem, show, season, episodes, seasonSearch=False, manua
finalResults.append(bestResult) finalResults.append(bestResult)
if manualSearch:
logger.log(u"Checking if we should snatch " + bestResult.name, logger.DEBUG) logger.log(u"Checking if we should snatch " + bestResult.name, logger.DEBUG)
any_qualities, best_qualities = Quality.splitQuality(show.quality) any_qualities, best_qualities = Quality.splitQuality(show.quality)
@ -538,6 +539,10 @@ def searchProviders(queueItem, show, season, episodes, seasonSearch=False, manua
queueItem.results = [bestResult] queueItem.results = [bestResult]
return queueItem return queueItem
# make sure we search every provider for results
if providerNum < len(providers):
continue
# remove duplicates and insures snatch of highest quality from results # remove duplicates and insures snatch of highest quality from results
for i1, result1 in enumerate(finalResults): for i1, result1 in enumerate(finalResults):
for i2, result2 in enumerate(finalResults): for i2, result2 in enumerate(finalResults):